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NCERT Solutions Class 7 Maths Chapter 2 Fractions and Decimals

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NCERT Class 7 Chapter 2 Maths Fractions and Decimals - FREE PDF Download

Here are the NCERT solutions for fractions and decimals Class 7. In order to improve their exam scores, students can practice answering various kinds of questions linked to this chapter either online or by downloading these files. In previous lessons, students have learned how to add and subtract decimals as well as fractions. In this lesson, students will learn how to multiply and divide decimals, as well as fractions. These Class 7 Maths Chapter 2 Solutions, which include fractions and decimals, have been created by experts in the field to help students prepare for their exams.

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Table of Content
1. NCERT Class 7 Chapter 2 Maths Fractions and Decimals - FREE PDF Download
2. Glance on Maths Chapter 2 Class 7 - Fractions and Decimals
3. Access Exercise Wise NCERT Solutions for Chapter 2 Maths Class 7
4. Exercises Under NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals
5. Access NCERT Solutions for Class 7 Maths Chapter 2 – Fractions and Decimals
6. NCERT Solutions for Class 7 Chapter 2 Maths PDF Download
7. Overview of Deleted Syllabus for CBSE Class 7 Maths Chapter 2 Fractions and Decimals
8. Class 7 Maths Chapter 2: Exercises Breakdown
9. Other Study Material for CBSE Class 7 Maths Chapter 2
10. Chapter-Specific NCERT Solutions for Class 7 Maths
FAQs


Glance on Maths Chapter 2 Class 7 - Fractions and Decimals

  • Basic calculations like adding, subtracting, comparing, and ranking fractions are covered in this chapter.

  • We work on word problems, such as applying concepts like fractions to real-life scenarios.

  • We cover higher-order thinking questions that test your ability to evaluate and resolve issues with decimals and fractions.

  • Focus on concepts like adding, subtracting, multiplying, and dividing fractions, and confidently convert between fractions and decimals.

  • This article contains chapter notes, important questions, and exercise links for Chapter 2 Fractions and Decimals, which you can download  as PDFs.

  • There are five exercises (31 fully solved questions) in class 7th maths chapter 2 Fractions and Decimal.


Access Exercise Wise NCERT Solutions for Chapter 2 Maths Class 7

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Exercises Under NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals

Exercise 2.1: Multiplication of Fractions

  • Multiplying Fractions by Whole Numbers: Understanding how to multiply fractions by whole numbers.

  • Multiplying Two Fractions: Learning the method to multiply two fractions.

  • Multiplying Mixed Numbers: Converting mixed numbers to improper fractions and then multiplying them.


Exercise 2.2: Division of Fractions

  • Reciprocal of a Fraction: Introduction to the concept of reciprocals.

  • Dividing Fractions by Whole Numbers: Method to divide fractions by whole numbers using reciprocals.

  • Dividing a Fraction by Another Fraction: Understanding the steps to divide one fraction by another fraction.

  • Word Problems: Applying division of fractions to solve real-life problems.


Exercise 2.3: Multiplication of Decimal Numbers

This section in Maths Class 7 Chapter 2 covers the rules and methods for multiplying decimal numbers. It includes step-by-step instructions for aligning the decimal points and performing multiplication, followed by placing the decimal point in the product correctly. Practical examples and problems help reinforce the concept and provide practice in multiplying decimals in various contexts.


Exercise 2.4: Division of Decimal Numbers

This section focuses on dividing decimal numbers, explaining how to handle the decimal point in both the dividend and the divisor. It includes methods for converting the divisor into a whole number by multiplying both the dividend and the divisor by a power of ten. The section in Class 7 Fractions and Decimals provides numerous examples and exercises to practice the division of decimals, ensuring a clear understanding of the process.


Access NCERT Solutions for Class 7 Maths Chapter 2 – Fractions and Decimals

Exercise - 2.1

1. Which of the drawings $(a)\,to\,(d)$ show:

(i). $\text{2 }\!\!\times\!\!\text{ }\frac{\text{1}}{\text{5}}$

(a) 

corresponds to d


Ans: corresponds to $\text{(d)}$  

Because,  $2\times \frac{1}{5}=\frac{1}{5}+\frac{1}{5}$                                                                


(ii). $\text{2 }\!\!\times\!\!\text{ }\frac{\text{1}}{\text{2}}$

(b)

corresponds to b


Ans: corresponds to $\text{(b)}$

Because, $2\times \frac{1}{2}=\frac{1}{2}+\frac{1}{2}$


(iii). $\text{3 }\!\!\times\!\!\text{ }\frac{\text{2}}{\text{3}}$

(c)

corresponds to a

 

Ans:  corresponds to $\text{(a)}$   

Because, $3\times \frac{2}{3}=\frac{2}{3}+\frac{2}{3}+\frac{2}{3}$ 

                                                                

(iv). $\text{3 }\!\!\times\!\!\text{ }\frac{\text{1}}{\text{4}}$

(d)

Corresponds to c


Ans: Corresponds to $\text{(c)}$

Because, $3\times \frac{1}{4}=\frac{1}{4}+\frac{1}{4}+\frac{1}{4}$ 


2. Some pictures $\left( \text{a} \right)\,\text{to}\,\left( \text{c} \right)$ are given below. Tell which of them show: 

(i). $\text{3 }\!\!\times\!\!\text{ }\frac{\text{1}}{\text{5}}\text{=}\frac{\text{3}}{\text{5}}$

(a)

Corresponds to (c)


Ans: Corresponds to $\text{(c)}$                    

Because, $3\times \frac{1}{5}=\frac{1}{5}+\frac{1}{5}+\frac{1}{5}$  

                                             

(ii). $\text{2 }\!\!\times\!\!\text{ }\frac{\text{1}}{\text{3}}\text{=}\frac{\text{2}}{\text{3}}$ 

(b)

Corresponds to (a)


Ans: Corresponds to $\text{(a)}$                   

Because, $2\times \frac{1}{3}=\frac{1}{3}+\frac{1}{3}$ 

                                                                                             

(iii). $\text{3 }\!\!\times\!\!\text{ }\frac{\text{3}}{\text{4}}\text{=2}\frac{\text{1}}{\text{4}}$

(c)

Corresponds to (b)


Ans: Corresponds to $\text{(b)}$                  

Because, $3\times \frac{3}{4}=\frac{3}{4}+\frac{3}{4}+\frac{3}{4}$      


3. Multiply and reduce to lowest form and convert into a mixed fraction:

(i). $\text{7 }\!\!\times\!\!\text{ }\frac{\text{3}}{\text{5}}$        

Ans: Multiplying and reducing to lowest form and converting into a mixed fraction,   

$7\times \frac{3}{5}=\frac{7\times 3}{5}=\frac{21}{5}=4\frac{1}{5}$

    

(ii). $\text{4 }\!\!\times\!\!\text{ }\frac{\text{1}}{\text{3}}$ 

Ans: Multiplying and reducing to lowest form and converting into a mixed fraction,

$4\times \frac{1}{3}=\frac{4\times 1}{3}=\frac{4}{3}=1\frac{1}{3}$ 


(iii). $\text{2 }\!\!\times\!\!\text{ }\frac{\text{6}}{\text{7}}$    

Ans: Multiplying and reducing to lowest form and converting into a mixed fraction,

$2\times \frac{6}{7}=\frac{2\times 6}{7}=\frac{12}{7}=1\frac{5}{7}$       

           

(iv). $\text{5 }\!\!\times\!\!\text{ }\frac{\text{2}}{\text{9}}$ 

Ans: Multiplying and reducing to lowest form and converting into a mixed fraction,

$5\times \frac{2}{9}=\frac{5\times 2}{9}=\frac{10}{9}=1\frac{1}{9}$

                   

(v). $\frac{\text{2}}{\text{3}}\text{ }\!\!\times\!\!\text{ 4}$     

Ans: Multiplying and reducing to lowest form and converting into a mixed fraction,

$\frac{2}{3}\times 4=\frac{2\times 4}{3}=\frac{8}{3}=2\frac{2}{3}$   

       

(vi)  $\frac{\text{5}}{\text{2}}\text{ }\!\!\times\!\!\text{ 6}$    

Ans: Multiplying and reducing to lowest form and converting into a mixed fraction,

$\frac{5}{2}\times 6=5\times 3=15$


(vii)   $\text{11 }\!\!\times\!\!\text{ }\frac{\text{4}}{\text{7}}$    

Ans: Multiplying and reducing to lowest form and converting into a mixed fraction,

$11\times \frac{4}{7}=\frac{11\times 4}{7}=\frac{44}{7}=6\frac{2}{7}$ 


(viii)  $\text{20 }\!\!\times\!\!\text{ }\frac{\text{4}}{\text{5}}$ 

Ans: Multiplying and reducing to lowest form and converting into a mixed fraction,

$20\times \frac{4}{5}=4\times 4=16$


(ix)  $\text{13 }\!\!\times\!\!\text{ }\frac{\text{1}}{\text{3}}$      

Ans: Multiplying and reducing to lowest form and converting into a mixed fraction,    

$13\times \frac{1}{3}=\frac{13\times 1}{3}=\frac{13}{3}=4\frac{1}{3}$ 

    

(x)  $\text{15 }\!\!\times\!\!\text{ }\frac{\text{3}}{\text{5}}$ 

Ans: Multiplying and reducing to lowest form and converting into a mixed fraction,   

$15\times \frac{3}{5}=3\times 3=9$                


4. Shade: 

(i). $\frac{\text{1}}{\text{2}}$ of the circles in box

(ii).

Half of the circles in the box


Ans: Half of the circles in the box are,

$\frac{\text{1}}{\text{2}}\,\text{of}\,\text{12}\,\text{circles=}\frac{\text{1}}{\text{2}}\text{ }\!\!\times\!\!\text{ 12=6}\,\text{circles}$


Half of the circles in the box 2


(iii). $\frac{\text{2}}{\text{3}}$ of the triangles in box 

(b)

the triangles in box


Ans: Two-third of the triangles in the box are,$\frac{\text{2}}{\text{3}}\,\text{of}\,\text{9}\,\text{triangles=}\frac{\text{2}}{\text{3}}\text{ }\!\!\times\!\!\text{ 9=2 }\!\!\times\!\!\text{ 3=6}\,\text{triangles}$


the triangles in box 2


(iv). $\frac{\text{3}}{\text{5}}$ of the squares inbox


(v). (c)

the squares inbox


Ans: Three-fifth of the squares in the box are,

$\frac{\text{3}}{\text{5}}\,\text{of}\,\text{15}\,\text{squares=}\frac{\text{3}}{\text{5}}\text{ }\!\!\times\!\!\text{ 15=3 }\!\!\times\!\!\text{ 3=9}\,\text{squares}$


the squares in the box 2


5. Find

(a).$\frac{\text{1}}{\text{2}}\,\text{of}\,\text{(i)}\,\text{24}\,\text{(ii)}\,\text{46}$

Ans:

(i) Calculating the value,

$\frac{\text{1}}{\text{2}}\,\text{of}\,\text{24=12}$


(ii) Calculating the value,

$\frac{\text{1}}{\text{2}}\,\text{of}\,\text{46=23}$ 

                     

(b). $\frac{\text{2}}{\text{3}}\,\text{of}\,\text{(i)}\,\text{18}\,\text{(ii)}\,\text{27}$ 

Ans:

(i) Calculating the value, $\frac{\text{2}}{\text{3}}\,\text{of}\,\text{18=}\frac{\text{2}}{\text{3}}\text{ }\!\!\times\!\!\text{ 18=2 }\!\!\times\!\!\text{ 6=12}$


(ii) Calculating the value, $\frac{\text{2}}{\text{3}}\,\text{of}\,\text{27=}\frac{\text{2}}{\text{3}}\text{ }\!\!\times\!\!\text{ 27=2 }\!\!\times\!\!\text{ 9=18}$ 


(c)  $\frac{\text{3}}{\text{4}}\,\text{of}\,\text{(i)}\,\text{16}\,\text{(ii)}\,\text{36}$          

Ans:

(i) Calculating the value,

$\frac{\text{3}}{\text{4}}\,\text{of}\,\text{16=}\frac{\text{3}}{\text{4}}\text{ }\!\!\times\!\!\text{ 16=3 }\!\!\times\!\!\text{ 4=12}$


(ii) Calculating the value,

$\frac{\text{3}}{\text{4}}\,\text{of}\,36\text{=}\frac{\text{3}}{\text{4}}\text{ }\!\!\times\!\!\text{ 36=3 }\!\!\times\!\!\text{ 9=27}$  


(d)  $\frac{\text{4}}{\text{5}}\,\text{of}\,\text{(i)}\,\text{20}\,\text{(ii)}\,\text{35}$ 

Ans:

(i) Calculating the value,

$\frac{\text{4}}{\text{5}}\,\text{of}\,20\text{=}\frac{\text{4}}{\text{5}}\text{ }\!\!\times\!\!\text{ 20=4 }\!\!\times\!\!\text{ 4=16}$


(ii) Calculating the value,

$\frac{\text{4}}{\text{5}}\,\text{of}\,35\text{=}\frac{\text{4}}{\text{5}}\text{ }\!\!\times\!\!\text{ 35=4 }\!\!\times\!\!\text{ 7=28}$ 


6.   Multiply and express as a mixed fraction:

(a)  $\text{3 }\!\!\times\!\!\text{ 5}\frac{\text{1}}{\text{5}}$       

Ans: Multiplying and expressing the term as mixed fraction,

$3\times 5\frac{1}{5}=3\times \frac{26}{5}=\frac{3\times 26}{5}=\frac{78}{5}=15\frac{3}{5}$

                

(b) $\text{5 }\!\!\times\!\!\text{ 6}\frac{\text{3}}{\text{4}}$          

Ans: Multiplying and expressing the term as mixed fraction,

$5\times 6\frac{3}{4}=5\times \frac{27}{4}=\frac{5\times 27}{4}=\frac{135}{4}=33\frac{3}{4}$ 

       

(c) $\text{7 }\!\!\times\!\!\text{ 2}\frac{\text{1}}{\text{4}}$

Ans: Multiplying and expressing the term as mixed fraction,

$7\times 2\frac{1}{4}=7\times \frac{9}{4}=\frac{7\times 9}{4}=\frac{63}{4}=15\frac{3}{4}$        

 

(d)  $\text{4 }\!\!\times\!\!\text{ 6}\frac{\text{1}}{\text{3}}$ 

Ans: Multiplying and expressing the term as mixed fraction,

$4\times 6\frac{1}{3}=4\times \frac{19}{3}=\frac{4\times 19}{3}=\frac{76}{3}=25\frac{1}{3}$ 

                      

(e)  $\text{3}\frac{\text{1}}{\text{4}}\text{ }\!\!\times\!\!\text{ 6}$ 

Ans: Multiplying and expressing the term as mixed fraction,

$3\frac{1}{4}\times 6=\frac{13}{4}\times 6=\frac{13\times 3}{2}=\frac{39}{2}=19\frac{1}{2}$  

                

(f)  $\text{3}\frac{\text{2}}{\text{5}}\text{ }\!\!\times\!\!\text{ 8}$ 

Ans: Multiplying and expressing the term as mixed fraction,

$3\frac{2}{5}\times 8=\frac{17}{5}\times 8=\frac{17\times 8}{5}=\frac{136}{5}=27\frac{1}{5}$


7. Find:

(a)  $\frac{\text{1}}{\text{2}}\,\text{of}\,\text{(i)}\,\text{2}\frac{\text{3}}{\text{4}}\,\text{(ii)}\,\text{4}\frac{\text{2}}{\text{9}}$             

Ans:

(i) Calculating the value, \[\frac{\text{1}}{\text{2}}\,\text{of}\,\text{2}\frac{\text{3}}{\text{4}}\text{=}\frac{\text{1}}{\text{2}}\text{ }\!\!\times\!\!\text{ 2}\frac{\text{3}}{\text{4}}\text{=}\frac{\text{1}}{\text{2}}\text{ }\!\!\times\!\!\text{ }\frac{\text{11}}{\text{4}}\text{=}\frac{\text{11}}{\text{8}}\text{=1}\frac{\text{3}}{\text{8}}\] 


(ii) Calculating the value, \[\frac{\text{1}}{\text{2}}\,\text{of}\,\text{4}\frac{\text{2}}{\text{9}}\text{=}\frac{\text{1}}{\text{2}}\text{ }\!\!\times\!\!\text{ 4}\frac{\text{2}}{\text{9}}\text{=}\frac{\text{1}}{\text{2}}\text{ }\!\!\times\!\!\text{ }\frac{\text{38}}{\text{9}}\text{=}\frac{\text{19}}{\text{9}}\text{=2}\frac{\text{1}}{\text{9}}\] 


(b)  $\frac{\text{5}}{\text{8}}\,\text{of}\,\text{(i)}\,\text{3}\frac{\text{5}}{\text{6}}\,\text{(ii)}\,\text{9}\frac{\text{2}}{\text{3}}$ 

Ans:

(i) Calculating the value, \[\frac{\text{5}}{\text{8}}\,\text{of}\,\text{3}\frac{\text{5}}{\text{6}}\text{=}\frac{\text{5}}{\text{8}}\text{ }\!\!\times\!\!\text{ 3}\frac{\text{5}}{\text{6}}\text{=}\frac{\text{5}}{\text{8}}\text{ }\!\!\times\!\!\text{ }\frac{\text{23}}{\text{6}}\text{=}\frac{\text{115}}{\text{48}}\text{=2}\frac{\text{19}}{\text{48}}\] 


(ii) Calculating the value, \[\frac{\text{5}}{\text{8}}\,\text{of}\,\text{9}\frac{\text{2}}{\text{3}}\text{=}\frac{\text{5}}{\text{8}}\text{ }\!\!\times\!\!\text{ 9}\frac{\text{2}}{\text{3}}\text{=}\frac{\text{5}}{\text{8}}\text{ }\!\!\times\!\!\text{ }\frac{\text{29}}{\text{3}}\text{=}\frac{\text{145}}{\text{24}}\text{=6}\frac{\text{1}}{\text{24}}\] 


8.  Vidya and Pratap went for a picnic. Their mother gave them a water bottle that contained $\text{5}$ liters of water. Vidya consumed $\frac{\text{2}}{\text{5}}$ of the water. Pratap consumed the remaining water.

(i). How much water did Vidya drink?

Ans:   Water consumed by Vidya is,$\text{=}\frac{\text{2}}{\text{5}}\,\text{of}\,\text{5}\,\text{litres=}\frac{\text{2}}{\text{5}}\text{ }\!\!\times\!\!\text{ 5=2}\,\text{litres}$ 

Hence, Vidya drank $2$ litres of water from the bottle.


(ii). What fraction of the total quantity of water did Pratap drink?

Ans: Water consumed by Pratap \[\text{= }\left( \text{1-}\frac{\text{2}}{\text{5}} \right)\text{  }\]part of bottle

Pratap consumed $\frac{\text{3}}{\text{5}}\,\text{of}\,\text{5}\,\text{litres}\,\text{water=}\frac{\text{3}}{\text{5}}\text{ }\!\!\times\!\!\text{ 5=3}\,\text{lites}$ 

Hence, Pratap drank $\frac{3}{5}$ part of the total quantity of water present in the bottle.


Exercise - 2.2

1. Find:

(i) $\frac{\text{1}}{\text{4}}\,\text{of}$ (a) $\frac{\text{1}}{\text{4}}$ (b) $\frac{\text{3}}{\text{5}}$ (c) $\frac{\text{4}}{\text{3}}$ 

Ans:

(a) Calculating the value,

$\frac{\text{1}}{\text{4}}\,\text{of}\,\frac{\text{1}}{\text{4}}\text{=}\frac{\text{1}}{\text{4}}\text{ }\!\!\times\!\!\text{ }\frac{\text{1}}{\text{4}}\text{=}\frac{\text{1 }\!\!\times\!\!\text{ 1}}{\text{4 }\!\!\times\!\!\text{ 4}}\text{=}\frac{\text{1}}{\text{16}}$ 

(b) Calculating the value,

$\frac{\text{1}}{\text{4}}\,\text{of}\,\frac{\text{3}}{\text{5}}\text{=}\frac{\text{1}}{\text{4}}\text{ }\!\!\times\!\!\text{ }\frac{\text{3}}{\text{4}}\text{=}\frac{\text{1 }\!\!\times\!\!\text{ 3}}{\text{4 }\!\!\times\!\!\text{ 4}}\text{=}\frac{\text{3}}{\text{16}}$ 


(c) Calculating the value,

$\frac{\text{1}}{\text{4}}\,\text{of}\,\frac{\text{4}}{\text{3}}\text{=}\frac{\text{1}}{\text{4}}\text{ }\!\!\times\!\!\text{ }\frac{\text{4}}{\text{3}}\text{=}\frac{\text{1 }\!\!\times\!\!\text{ 4}}{\text{4 }\!\!\times\!\!\text{ 3}}\text{=}\frac{\text{1}}{\text{3}}$ 


(ii) \[\frac{\text{1}}{\text{7}}\,\text{of}\] (a) \[\frac{\text{2}}{\text{9}}\] (b) \[\frac{\text{6}}{\text{5}}\] (c) $\frac{\text{3}}{\text{10}}$ 

Ans:

(a) Calculating the value,

$\frac{\text{1}}{\text{7}}\,\text{of}\,\frac{\text{2}}{\text{9}}\text{=}\frac{\text{1}}{\text{7}}\text{ }\!\!\times\!\!\text{ }\frac{\text{2}}{\text{9}}\text{=}\frac{\text{1 }\!\!\times\!\!\text{ 2}}{\text{7 }\!\!\times\!\!\text{ 9}}\text{=}\frac{\text{2}}{\text{63}}$ 


(b) Calculating the value,

$\frac{\text{1}}{\text{7}}\,\text{of}\,\frac{\text{2}}{\text{9}}\text{=}\frac{\text{1}}{\text{7}}\text{ }\!\!\times\!\!\text{ }\frac{\text{6}}{\text{5}}\text{=}\frac{\text{1 }\!\!\times\!\!\text{ 6}}{\text{7 }\!\!\times\!\!\text{ 5}}\text{=}\frac{\text{6}}{\text{35}}$ 


(c) Calculating the value,

$\frac{\text{1}}{\text{7}}\,\text{of}\,\frac{\text{2}}{\text{9}}\text{=}\frac{\text{1}}{\text{7}}\text{ }\!\!\times\!\!\text{ }\frac{\text{3}}{\text{10}}\text{=}\frac{\text{1 }\!\!\times\!\!\text{ 3}}{\text{7 }\!\!\times\!\!\text{ 10}}\text{=}\frac{3}{70}$ 


2. Multiply and reduce to lowest form (if possible):

(i) $\frac{\text{2}}{\text{3}}\text{ }\!\!\times\!\!\text{ 2}\frac{\text{2}}{\text{3}}$ 

Ans: Multiplying and reducing to lowest form,  

$\frac{2}{3}\times 2\frac{2}{3}=\frac{2}{3}\times \frac{8}{3}=\frac{2\times 8}{3\times 3}=\frac{16}{9}=1\frac{7}{9}$ 

(ii) $\frac{\text{2}}{\text{7}}\text{ }\!\!\times\!\!\text{ }\frac{\text{7}}{\text{9}}$

Ans: Multiplying and reducing to lowest form,  

$\frac{2}{7}\times \frac{7}{9}=\frac{2\times 7}{7\times 9}=\frac{2}{9}$


(iii) $\frac{\text{3}}{\text{8}}\text{ }\!\!\times\!\!\text{ }\frac{\text{6}}{\text{4}}$ 

Ans: Multiplying and reducing to lowest form, 

$\frac{3}{8}\times \frac{6}{4}=\frac{3\times 6}{8\times 4}=\frac{3\times 3}{8\times 2}=\frac{9}{16}$

(iv) $\frac{\text{9}}{\text{5}}\text{ }\!\!\times\!\!\text{ }\frac{\text{3}}{\text{5}}$ 

Ans: Multiplying and reducing to lowest form, 

$\frac{9}{5}\times \frac{3}{5}=\frac{9\times 3}{5\times 5}=\frac{27}{25}=1\frac{2}{25}$


(v) $\frac{\text{1}}{\text{3}}\text{ }\!\!\times\!\!\text{ }\frac{\text{15}}{\text{8}}$ 

Ans: Multiplying and reducing to lowest form,

$\frac{1}{3}\times \frac{15}{8}=\frac{1\times 15}{3\times 8}=\frac{1\times 5}{1\times 8}=\frac{5}{8}$

(vi) $\frac{\text{11}}{\text{2}}\text{ }\!\!\times\!\!\text{ }\frac{\text{3}}{\text{10}}$ 

Ans: Multiplying and reducing to lowest form,  

$\frac{11}{2}\times \frac{3}{10}=\frac{11\times 3}{2\times 10}=\frac{33}{20}=1\frac{3}{20}$ 

(vii) $\frac{\text{4}}{\text{5}}\text{ }\!\!\times\!\!\text{ }\frac{\text{12}}{\text{7}}$ 

Ans: Multiplying and reducing to lowest form,  

$\frac{4}{5}\times \frac{12}{7}=\frac{4\times 12}{5\times 7}=\frac{48}{35}=1\frac{13}{35}$


3. Multiply the following fractions:

(i) $\frac{\text{2}}{\text{5}}\text{ }\!\!\times\!\!\text{ 5}\frac{\text{1}}{\text{4}}$

Ans: Performing multiplication,

$\frac{2}{5}\times 5\frac{1}{4}=\frac{2}{5}\times \frac{21}{4}=\frac{2\times 21}{5\times 4}=\frac{1\times 21}{5\times 2}=\frac{21}{10}=2\frac{1}{10}$ 


(ii) $\text{6}\frac{\text{2}}{\text{5}}\text{ }\!\!\times\!\!\text{ }\frac{\text{7}}{\text{9}}$ 

Ans: Performing multiplication,

$6\frac{2}{5}\times \frac{7}{9}=\frac{32}{5}\times \frac{7}{9}=\frac{32\times 7}{5\times 9}=\frac{224}{45}=4\frac{44}{45}$


(iii) $\frac{\text{3}}{\text{2}}\text{ }\!\!\times\!\!\text{ 5}\frac{\text{1}}{\text{3}}$ 

Ans: Performing multiplication,

$\frac{3}{2}\times 5\frac{1}{3}=\frac{3}{2}\times \frac{16}{3}=\frac{48}{6}=8$ 


(iv) $\frac{\text{5}}{\text{6}}\text{ }\!\!\times\!\!\text{ 2}\frac{\text{3}}{\text{7}}$ 

Ans: Performing multiplication,

$\frac{5}{6}\times 2\frac{3}{7}=\frac{5}{6}\times \frac{17}{7}=\frac{85}{42}=2\frac{1}{42}$ 

(v) $\text{3}\frac{\text{2}}{\text{5}}\text{ }\!\!\times\!\!\text{ }\frac{\text{4}}{\text{7}}$

Ans: Performing multiplication,

$3\frac{2}{5}\times \frac{4}{7}=\frac{17}{7}\times \frac{4}{7}=\frac{68}{35}=1\frac{33}{35}$


(vi) $\text{2}\frac{\text{3}}{\text{5}}\text{ }\!\!\times\!\!\text{ 3}$ 

Ans: Performing multiplication,

$2\frac{3}{5}\times 3=\frac{13}{5}\times \frac{3}{1}=\frac{13\times 3}{5\times 1}=\frac{39}{5}=7\frac{4}{5}$


(vii) $\text{3}\frac{\text{4}}{\text{7}}\text{ }\!\!\times\!\!\text{ }\frac{\text{3}}{\text{5}}$ 

Ans: Performing multiplication,

$3\frac{4}{7}\times \frac{3}{5}=\frac{25}{7}\times \frac{3}{5}=\frac{5\times 3}{7\times 1}=\frac{15}{7}=2\frac{1}{7}$


4. Which is greater:

(i) $\frac{\text{2}}{\text{7}}\,\text{of}\,\frac{\text{3}}{\text{4}}\,\text{or}\,\frac{\text{3}}{\text{5}}\,\text{of}\,\frac{\text{5}}{\text{8}}$

Ans: Calculating the greater term,

$\frac{\text{2}}{\text{7}}\,\text{of}\,\frac{\text{3}}{\text{4}}\,\text{or}\,\frac{\text{3}}{\text{5}}\,\text{of}\,\frac{\text{5}}{\text{8}}$                

$\Rightarrow \frac{\text{2}}{\text{7}}\text{ }\!\!\times\!\!\text{ }\frac{\text{3}}{\text{4}}\,\text{or}\,\frac{\text{3}}{\text{5}}\text{ }\!\!\times\!\!\text{ }\frac{\text{5}}{\text{8}}$ 

$\Rightarrow \frac{\text{3}}{\text{14}}\,\text{or}\,\frac{\text{3}}{\text{8}}$

$\Rightarrow \frac{3}{14}<\frac{3}{8}$ 

Hence, $\frac{\text{3}}{\text{5}}\,\text{of}\,\frac{\text{5}}{\text{8}}$ is greater.


(ii) $\frac{\text{1}}{\text{2}}\,\text{of}\,\frac{\text{6}}{\text{7}}\,\text{or}\,\frac{\text{2}}{\text{3}}\,\text{of}\,\frac{\text{3}}{\text{7}}$ 

Ans:

Calculating the greater term,

$\frac{\text{1}}{\text{2}}\,\text{of}\,\frac{\text{6}}{\text{7}}\,\text{or}\,\frac{\text{2}}{\text{3}}\,\text{of}\,\frac{\text{3}}{\text{7}}$                

$\Rightarrow \frac{\text{1}}{\text{2}}\text{ }\!\!\times\!\!\text{ }\frac{\text{6}}{\text{7}}\,\text{or}\,\frac{\text{2}}{\text{3}}\text{ }\!\!\times\!\!\text{ }\frac{\text{3}}{\text{7}}$ 

$\Rightarrow \frac{\text{6}}{\text{14}}\,\text{or}\,\frac{\text{2}}{\text{7}}$ $\Rightarrow \frac{\text{6}}{\text{14}}>\frac{\text{2}}{\text{7}}$ 

Hence, $\frac{\text{1}}{\text{2}}\,\text{of}\,\frac{\text{6}}{\text{7}}$ is greater.


5. Saili plants \[\text{4}\] saplings in a row in her garden. The distance between

two adjacent saplings is \[\frac{\text{3}}{\text{4}}\] m. Find the 

distance between the first and the last sapling. 

Ans: Given: Saili plants \[4\] saplings in a row where the distance between two 

adjacent saplings $=\frac{3}{4}$m.


The number of gaps in saplings


The number of gaps in saplings \[=\text{ }3\] 

Hence, 

The distance between the first and the last saplings$\text{=3 }\!\!\times\!\!\text{ }\frac{\text{3}}{\text{4}}\text{=}\frac{\text{9}}{\text{4}}\text{m=2}\frac{\text{1}}{\text{4}}\text{m}$

Therefore, the distance between the first and the last saplings is $\text{2}\frac{\text{1}}{\text{4}}\,\text{m}$


6. Lipika reads a book for $\text{1}\frac{\text{3}}{\text{4}}$ hours every day. 

She reads the entire book in \[\text{6}\] days. How many hours in all were 

required by her to read the book?

Ans: Given: Time taken for reading a book by Lipika $=1\frac{3}{4}$ hours.

Lipika reads the entire book in $6$ days

Calculating the Total hours taken by Lipika to read the entire book,

$=1\frac{3}{4}\times 6=\frac{7}{4}\times 6=\frac{21}{2}=10\frac{1}{2}$ hours.

Hence, it would take $10$ hours to read the book.


7. A car runs $\text{16}$ km using \[\text{1}\] litre of petrol. How much 

distance will it cover using   $\text{2}\frac{\text{3}}{\text{4}}$ litres of 

petrol?

Ans: Given: A car covers the distance$\text{=16}\,\text{km}$ in $1$ litre of 

petrol.

Calculating the distance covered by car in $2\frac{3}{4}$ litres of petrol,

Distance$\text{=2}\frac{\text{3}}{\text{4}}\,\text{of}\,\text{16}\,\text{km=}\frac{\text{11}}{\text{4}}\text{ }\!\!\times\!\!\text{ 16=44}\,\text{km}$

Therefore, car will cover a distance of $44$ km in $2\frac{3}{4}$ litres of petrol.


8. (a)

(i) Provide the number in the box , such that 

$\frac{\text{2}}{\text{3}}\text{ }\!\!\times\!\!\text{ }\text{=}\frac{\text{10}}{\text{30}}$ 

Ans: The number inside the box should be $\frac{2}{3}\times =\frac{10}{30}$ 


(ii) The simplest form of the number obtained in $$ is _____.

Ans: The simplest form of the number obtained in 

$\frac{\text{5}}{\text{10}}\,\text{is}\,\frac{\text{1}}{\text{2}}$


(b) 

(i) Provide the number in the box $$ , such that $\frac{3}{5}\times =\frac{24}{75}$.

Ans: The number inside the box should be $\frac{3}{5}\times =\frac{24}{75}$ 

(ii) The simplest form of the number obtained in is______.

Ans: The simplest form of the number obtained in 

$\frac{\text{8}}{\text{15}}\,\text{is}\,\frac{\text{8}}{\text{15}}$


Exercise - 2.3

1. Find:

(i) $\text{12 }\!\!\div\!\!\text{ }\frac{\text{3}}{\text{4}}$ 

Ans: Calculating the value,

$12\div \frac{3}{4}=12\times \frac{4}{3}=16$


(ii) $\text{14 }\!\!\div\!\!\text{ }\frac{\text{5}}{\text{6}}$ 

Ans: Calculating the value,

$14\div \frac{5}{6}=14\times \frac{6}{5}=\frac{84}{5}=16\frac{4}{5}$ 


(iii) $\text{8 }\!\!\div\!\!\text{ }\frac{\text{7}}{\text{3}}$ 

Ans:  Calculating the value,

$8\div \frac{7}{3}=8\times \frac{3}{7}=\frac{24}{7}=3\frac{3}{7}$

 

(iv) $\text{4 }\!\!\div\!\!\text{ }\frac{\text{8}}{\text{3}}$ 

Ans: Calculating the value,

$4\div \frac{8}{3}=4\times \frac{3}{8}=\frac{3}{2}=1\frac{1}{2}$


(v) $\text{3 }\!\!\div\!\!\text{ 2}\frac{\text{1}}{\text{3}}$ 

Ans: Calculating the value,

$3\div 2\frac{1}{3}=3\div \frac{7}{3}=3\times \frac{3}{7}=\frac{9}{7}=1\frac{2}{7}$           


(vi) \[\text{5 }\!\!\div\!\!\text{ 3}\frac{\text{4}}{\text{7}}\] 

Ans: Calculating the value,

$5\div 3\frac{4}{7}=5\div \frac{25}{7}=5\times \frac{7}{25}=\frac{7}{5}=1\frac{2}{5}$


2. Find the reciprocal of each of the following fractions. Classify the 

reciprocals as proper fraction, improper fractions and whole numbers.

(i) $\frac{\text{3}}{\text{7}}$

Ans: Calculating the reciprocal and stating the type of the fraction,

Reciprocal of $\frac{\text{3}}{\text{7}}\text{=}\frac{\text{7}}{\text{3}}\to \text{Improper}\,\text{fraction}$  


(ii) $\frac{\text{5}}{\text{8}}$

Ans: Calculating the reciprocal and stating the type of the fraction,

Reciprocal of$\frac{\text{5}}{\text{8}}\text{=}\frac{\text{8}}{\text{5}}\to \text{Improper}\,\text{fraction}$


(iii) $\frac{\text{9}}{\text{7}}$

Ans: Calculating the reciprocal and stating the type of the fraction,

Reciprocal of $\frac{\text{9}}{\text{7}}\text{=}\frac{\text{7}}{\text{9}}\to \text{Proper}\,\text{fraction}$


(iv) $\frac{\text{6}}{\text{5}}$ 

Ans: Calculating the reciprocal and stating the type of the fraction,

Reciprocal of $\frac{\text{6}}{\text{5}}\text{=}\frac{\text{5}}{\text{6}}\to \text{Proper}\,\text{fraction}$


(v) $\frac{\text{12}}{\text{7}}$ 

Ans: Calculating the reciprocal and stating the type of the fraction,

Reciprocal of $\frac{\text{12}}{\text{7}}\text{=}\frac{\text{7}}{\text{12}}\to \text{Proper}\,\text{fraction}$  


(vi) $\frac{\text{1}}{\text{8}}$

Ans: Calculating the reciprocal and stating the type of the fraction,

Reciprocal of $\frac{\text{9}}{\text{7}}\text{=8}\to \text{Whole number}$


(vii) $\frac{\text{1}}{\text{11}}$ 

Ans: Calculating the reciprocal and stating the type of the fraction,

Reciprocal of $\frac{\text{1}}{\text{11}}\text{=11}\to \text{Whole number}$


3. Find:

(i) $\frac{\text{7}}{\text{3}}\text{ }\!\!\div\!\!\text{ 2}$ 

Ans: Calculating the value,

$\frac{7}{3}\div 2=\frac{7}{3}\times \frac{1}{2}=\frac{7\times 1}{3\times 2}=\frac{7}{6}=1\frac{1}{6}$


(ii) $\frac{\text{4}}{\text{9}}\text{ }\!\!\div\!\!\text{ 5}$

Ans: Calculating the value,

$\frac{4}{9}\div 5=\frac{4}{9}\times \frac{1}{5}=\frac{4\times 1}{9\times 5}=\frac{4}{45}$ 


(iii) $\frac{\text{6}}{\text{13}}\text{ }\!\!\div\!\!\text{ 7}$ 

Ans: Calculating the value,

$\frac{6}{13}\div 7=\frac{6}{13}\times \frac{1}{7}=\frac{6\times 1}{13\times 7}=\frac{6}{91}$ 


(iv) $\text{4}\frac{\text{1}}{\text{3}}\text{ }\!\!\div\!\!\text{ 3}$

Ans:  Calculating the value,

$4\frac{1}{3}\div 3=\frac{13}{3}\div 3=\frac{13}{3}\times \frac{1}{3}=\frac{13}{9}=1\frac{4}{9}$


(v) $\text{3}\frac{\text{1}}{\text{2}}\text{ }\!\!\div\!\!\text{ 4}$ 

Ans: Calculating the value,

$3\frac{1}{2}\div 4=\frac{7}{2}\div 4=\frac{7}{2}\times \frac{1}{4}=\frac{7}{8}$


(vi) $\text{4}\frac{\text{3}}{\text{7}}\text{ }\!\!\div\!\!\text{ 7}$ 

Ans: Calculating the value,

$4\frac{3}{7}\div 7=\frac{31}{7}\div 7=\frac{31}{7}\times \frac{1}{7}=\frac{31}{49}$


4. Find:

(i) $\frac{\text{2}}{\text{5}}\text{ }\!\!\div\!\!\text{ }\frac{\text{1}}{\text{2}}$

Ans:  Calculating the value,

$\frac{2}{5}\div \frac{1}{2}=\frac{2}{5}\times \frac{2}{1}=\frac{2\times 2}{5\times 1}=\frac{4}{5}$ 


(ii) $\frac{\text{4}}{\text{9}}\text{ }\!\!\div\!\!\text{ }\frac{\text{2}}{\text{3}}$ 

Ans: Calculating the value,

$\frac{4}{9}\div \frac{2}{3}=\frac{4}{9}\times \frac{3}{2}=\frac{2}{3}$


(iii) $\frac{\text{3}}{\text{7}}\text{ }\!\!\div\!\!\text{ }\frac{\text{8}}{\text{7}}$

Ans:  Calculating the value,

$\frac{3}{7}\div \frac{8}{7}=\frac{3}{7}\times \frac{7}{8}=\frac{3}{8}$

(iv) $\text{2}\frac{\text{1}}{\text{3}}\text{ }\!\!\div\!\!\text{ }\frac{\text{3}}{\text{5}}$ 

Ans: Calculating the value,

$2\frac{1}{3}\div \frac{3}{5}=\frac{7}{3}\div \frac{3}{5}=\frac{7}{3}\times \frac{5}{3}=\frac{35}{9}=3\frac{8}{9}$


(v) $\text{3}\frac{\text{1}}{\text{2}}\text{ }\!\!\div\!\!\text{ }\frac{\text{8}}{\text{3}}$ 

Ans: Calculating the value,

$3\frac{1}{2}\div \frac{8}{3}=\frac{7}{2}\div \frac{3}{8}=\frac{7}{2}\times \frac{3}{8}=\frac{7\times 3}{2\times 8}=\frac{21}{16}=1\frac{5}{16}$


(vi) $\frac{\text{2}}{\text{5}}\text{ }\!\!\div\!\!\text{ 1}\frac{\text{1}}{\text{2}}$

Ans: Calculating the value,

$2\frac{1}{3}\div \frac{3}{5}=\frac{2}{5}\div 1\frac{1}{2}=\frac{2}{5}\div \frac{3}{2}=\frac{2}{5}\times \frac{2}{3}=\frac{2\times 2}{5\times 3}=\frac{4}{15}$


(vii) $\text{3}\frac{\text{1}}{\text{5}}\text{ }\!\!\div\!\!\text{ 1}\frac{\text{2}}{\text{3}}$

Ans:  Calculating the value,

$3\frac{1}{5}\div 1\frac{2}{3}=\frac{16}{5}\div \frac{5}{3}=\frac{16}{5}\times \frac{3}{5}=\frac{16\times 3}{5\times 5}=\frac{48}{25}=1\frac{23}{25}$


(viii) $\text{2}\frac{\text{1}}{\text{5}}\text{ }\!\!\div\!\!\text{ 1}\frac{\text{1}}{\text{5}}$ 

Ans: Calculating the value,

$2\frac{1}{5}\div 1\frac{1}{5}=\frac{11}{5}\div \frac{6}{5}=\frac{11}{5}\times \frac{5}{6}=\frac{11}{6}=1\frac{5}{6}$


Exercise 2.4

1. Find:

(i) $\text{0}\text{.2 }\!\!\times\!\!\text{ 6}$ 

Ans: Calculating the value,

\[0.2\times 6=1.2\]


(ii) $\text{8 }\!\!\times\!\!\text{ 4}\text{.6}$

Ans:  Calculating the value,

\[8\times 4.6=36.8\]


(iii) $\text{2}\text{.71 }\!\!\times\!\!\text{ 5}$ 

Ans: Calculating the value,

\[2.71\times 5=13.55\]


(iv) $\text{20}\text{.1 }\!\!\times\!\!\text{ 4}$ 

Ans: Calculating the value,

\[20.1\times 4=80.4\]


(v) $\text{0}\text{.05 }\!\!\times\!\!\text{ 7}$ 

Ans: Calculating the value,

\[0.05\times 7=0.35\]


(vi) $\text{211}\text{.02 }\!\!\times\!\!\text{ 4}$ 

Ans: Calculating the value,

\[211.02\times 4=844.08\]


(vii) $\text{2 }\!\!\times\!\!\text{ 0}\text{.86}$ 

Ans: Calculating the value,

\[2\times 0.86=1.72\]


2. Find the area of rectangle whose length is \[\text{5}\text{.7 cm}\] and 

breadth is \[\text{3 cm}\text{.}\]

Ans: Given: The \[\text{Length of rectangle = 5}\text{.7 cm and Breadth of 

rectangle = 3 cm}\] 

Applying the area of rectangle formula,

\[\text{Area of rectangle = Length x Breadth}\] 

\[\text{= 5}\text{.7 x 3 = 17}\text{.1 c}{{\text{m}}^{2}}\]  

Hence, the area of rectangle is $\text{17}\text{.1}\,\text{c}{{\text{m}}^{\text{2}}}$.

 

3. Find:

(i) \[\text{1}\text{.3 }\!\!\times\!\!\text{ 10}\] 

Ans: Calculating the value,

$1.3\times 10=13.0$


(ii) \[\text{36}\text{.8 }\!\!\times\!\!\text{ 10}\] 

Ans: Calculating the value,

$36.8\times 10=368.0$


(iii) \[\text{153}\text{.7 }\!\!\times\!\!\text{ 10}\] 

Ans: Calculating the value,

$153.7\times 10=1537.0$


(iv) \[\text{168}\text{.07 }\!\!\times\!\!\text{ 10}\]

Ans: Calculating the value,

$168.07\times 10=1680.7$


(v) \[\text{31}\text{.1 }\!\!\times\!\!\text{ 100}\] 

Ans: Calculating the value,

$31.1\times 100=3110.0$


(vi) \[\text{156}\text{.1 }\!\!\times\!\!\text{ 100}\] 

Ans: Calculating the value,

$156.1\times 100=15610.0$


(vii) \[\text{3}\text{.62 }\!\!\times\!\!\text{ 100}\] 

Ans: Calculating the value,

$3.62\times 100=362.0$

 

(viii) \[\text{43}\text{.07 }\!\!\times\!\!\text{ 100}\] 

Ans: Calculating the value,

$43.07\times 100=4307.0$


(ix) \[\text{0}\text{.5 }\!\!\times\!\!\text{ 10}\] 

Ans: Calculating the value,

$0.5\times 10=5.0$ 


(x) \[\text{0}\text{.08 }\!\!\times\!\!\text{ 10}\] 

Ans: Calculating the value,

$0.08\times 10=0.80$ 


(xi) \[\text{0}\text{.9 }\!\!\times\!\!\text{ 100}\]

Ans: Calculating the value,

$0.9\times 100=90.0$


(xii) \[\text{0}\text{.03 }\!\!\times\!\!\text{ 1000}\] 

Ans: Calculating the value,

$0.03\times 1000=30.0$ 


4. A two-wheeler covers a distance of\[\text{ }\!\!~\!\!\text{ 55}\text{.3 

km}\] 

in one litre of petrol. How much distance will it cover in \[\text{10 litres}\] of 

petrol?

Ans: Given: In one litre a two-wheeler covers a distance\[\text{ = 55}\text{.3 

km}\]

Since distance covered in one litre by a two-wheeler\[\text{ = 55}\text{.3 km}\]

\[\therefore \,\,\text{In 10 litrs, a two- wheeler covers a distance = 55}\text{.3 x 10 = 553}\text{.0 km}\] 

Hence, $553$ km distance will be covered by two-wheeler in $10$ litres of petrol.

5.  Find:

(i) $\text{2}\text{.5 }\!\!\times\!\!\text{ 0}\text{.3}$

Ans:  Calculating the value,

\[\text{2}\text{.5 x 0}\text{.3 = 0}\text{.75}\] 


(ii) $\text{0}\text{.1 }\!\!\times\!\!\text{ 51}\text{.7}$ 

Ans:  Calculating the value,

\[\text{0}\text{.1 x 51}\text{.7 = 5}\text{.17}\]


(iii) $\text{0}\text{.2 }\!\!\times\!\!\text{ 316}\text{.8}$ 

Ans: Calculating the value,

\[\text{0}\text{.2 x 316}\text{.8 = 63}\text{.36}\]


(iv) $\text{1}\text{.3 }\!\!\times\!\!\text{ 1}\text{.3}$ 

Ans: Calculating the value,

\[\text{1}\text{.3 x 3}\text{.1 = 4}\text{.03}\]


(v) $\text{0}\text{.5 }\!\!\times\!\!\text{ 0}\text{.05}$ 

Ans: Calculating the value,

\[\text{0}\text{.5 x 0}\text{.05 = 0}\text{.025}\]


(vi) $\text{11}\text{.2 }\!\!\times\!\!\text{ 0}\text{.15}$ 

Ans: Calculating the value,

\[\text{11}\text{.2 x 0}\text{.15 = 1}\text{.680 }\]


(vii) $\text{1}\text{.07 }\!\!\times\!\!\text{ 0}\text{.02}$ 

Ans: Calculating the value,

\[\text{1}\text{.07 x 0}\text{.02 = 0}\text{.0214}\]

(viii) $\text{10}\text{.05 }\!\!\times\!\!\text{ 1}\text{.05}$

Ans: Calculating the value,

\[\text{10}\text{.05 x 1}\text{.05 = 10}\text{.5525}\]


(ix) $\text{101}\text{.01 }\!\!\times\!\!\text{ 0}\text{.01}$ 

Ans: Calculating the value,

\[\text{101}\text{.01 x 0}\text{.01 = 1}\text{.0101}\]


(x) $\text{100}\text{.01 }\!\!\times\!\!\text{ 1}\text{.1}$

Ans: Calculating the value,

\[\text{100}\text{.01 x 1}\text{.1 = 110}\text{.11 }\]


Exercise 2.5

1. Find:

(i) \[\text{0}\text{.4  }\!\!\div\!\!\text{  2}\] 

Ans: Calculating the value,

\[0.4\div 2=\frac{4}{10}\times \frac{1}{2}=\frac{2}{10}=0.2\]

 

(ii) \[\text{0}\text{.35  }\!\!\div\!\!\text{  5}\] 

Ans: Calculating the value,

\[0.35\div 5=\frac{35}{100}\times \frac{1}{5}=\frac{7}{100}=0.07\]


(iii) \[\text{2}\text{.48  }\!\!\div\!\!\text{  4}\] 

Ans: Calculating the value,

\[2.48\div 4=\frac{248}{100}\times \frac{1}{4}=\frac{62}{100}=0.62\]


(iv) \[\text{65}\text{.4  }\!\!\div\!\!\text{  6}\] 

Ans: Calculating the value,

\[65.4\div 6=\frac{654}{10}\times \frac{1}{6}=\frac{109}{10}=10.9\]


(v) \[\text{651}\text{.2  }\!\!\div\!\!\text{  4}\] 

Ans: Calculating the value,

\[651.2\div 4=\frac{6512}{10}\times \frac{1}{4}=\frac{1628}{10}=162.8\]


(vi) \[\text{14}\text{.49  }\!\!\div\!\!\text{  7 }\] 

Ans: Calculating the value,

\[14.49\div 7=\frac{1449}{100}\times \frac{1}{7}=\frac{207}{100}=2.07\]


(vii) \[\text{3}\text{.96  }\!\!\div\!\!\text{  4}\]

Ans: Calculating the value,

\[3.96\div 4=\frac{396}{100}\times \frac{1}{4}=\frac{99}{100}=0.99\]


(viii) \[\text{0}\text{.80  }\!\!\div\!\!\text{  5}\] 

Ans: Calculating the value,

\[0.80\div 5=\frac{80}{100}\times \frac{1}{5}=\frac{16}{100}=0.16\]


2. Find:

(i) \[\text{4}\text{.8  }\!\!\div\!\!\text{  10}\] 

Ans: Performing the given calculation,

$4.8\div 10=\frac{4.8}{10}=0.48$

(ii) \[\text{52}\text{.5  }\!\!\div\!\!\text{  10}\] 

Ans: Performing the given calculation,

$52.5\div 10=\frac{52.5}{10}=5.25$

 

(iii) \[\text{0}\text{.7  }\!\!\div\!\!\text{  10}\] 

Ans: Performing the given calculation,

$0.7\div 10=\frac{0.7}{10}=0.07$


(iv) \[\text{33}\text{.1  }\!\!\div\!\!\text{  10}\]

Ans: Performing the given calculation,

$33.1\div 10=\frac{33.1}{10}=3.31$


(v) \[\text{272}\text{.23  }\!\!\div\!\!\text{  10}\] 

Ans: Performing the given calculation,

$272.23\div 10=\frac{272.23}{10}=27.223$


(vi) \[\text{0}\text{.56  }\!\!\div\!\!\text{  10 }\] 

Ans: Performing the given calculation,

$0.56\div 10=\frac{0.56}{10}=0.056$


(vii) \[\text{3}\text{.97  }\!\!\div\!\!\text{  10}\] 

Ans: Performing the given calculation,

$3.97\div 10=\frac{3.97}{10}=0.397$


3. Find:

(i) \[\text{2}\text{.7  }\!\!\div\!\!\text{  100}\] 

Ans: Converting the terms in fraction form and calculating the value,

$2.7\div 100=\frac{27}{10}\times \frac{1}{100}=\frac{27}{1000}=0.027$ 


(ii) \[\text{0}\text{.3  }\!\!\div\!\!\text{  100 }\]

Ans: Converting the terms in fraction form and calculating the value,

$0.3\div 100=\frac{3}{10}\times \frac{1}{100}=\frac{3}{1000}=0.003$


(iii) \[\text{0}\text{.78  }\!\!\div\!\!\text{  100}\] 

Ans: Converting the terms in fraction form and calculating the value,

$0.78\div 100=\frac{78}{10}\times \frac{1}{100}=\frac{78}{1000}=0.0078$


(iv) \[\text{432}\text{.6  }\!\!\div\!\!\text{  100}\] 

Ans: Converting the terms in fraction form and calculating the value,

$432.6\div 100=\frac{4326}{10}\times \frac{1}{100}=\frac{4326}{1000}=4.326$


(v) \[\text{23}\text{.6  }\!\!\div\!\!\text{  100}\] 

Ans: Converting the terms in fraction form and calculating the value,$23.6\div 100=\frac{236}{10}\times \frac{1}{100}=\frac{236}{1000}=0.236$


(vi) \[\text{98}\text{.53  }\!\!\div\!\!\text{  100}\] 

Ans: Converting the terms in fraction form and calculating the value,

$98.53\div 100=\frac{9853}{10}\times \frac{1}{100}=\frac{9853}{1000}=0.9853$


4. Find:

(i) \[\text{7}\text{.9  }\!\!\div\!\!\text{  1000}\] 

Ans: Converting the terms in fraction form and calculating the value,

$7.9\div 1000=\frac{79}{10}\times \frac{1}{1000}=\frac{79}{10000}=0.0079$ 


(ii) \[\text{26}\text{.3  }\!\!\div\!\!\text{  1000}\]

Ans: Converting the terms in fraction form and calculating the value,

$26.3\div 1000=\frac{263}{10}\times \frac{1}{1000}=\frac{263}{10000}=0.0263$


(iii) \[\text{38}\text{.53  }\!\!\div\!\!\text{  1000}\] 

Ans: Converting the terms in fraction form and calculating the value,

$38.53\div 1000=\frac{3853}{10}\times \frac{1}{1000}=\frac{3853}{10000}=0.03853$


(iv) \[\text{128}\text{.9  }\!\!\div\!\!\text{  1000}\] 

Ans: Converting the terms in fraction form and calculating the value,

$128.9\div 1000=\frac{1289}{10}\times \frac{1}{1000}=\frac{1289}{10000}=0.1289$


(v) \[\text{0}\text{.5  }\!\!\div\!\!\text{  1000}\] 

Ans: Converting the terms in fraction form and calculating the value,

$0.5\div 1000=\frac{5}{10}\times \frac{1}{1000}=\frac{5}{10000}=0.0005$


5. Find:

(i) \[\text{7  }\!\!\div\!\!\text{  3}\text{.5}\] 

Ans: Converting the terms in fraction form and calculating the value,

$7\div 3.5=7\div \frac{35}{10}=7\times \frac{10}{35}=\frac{10}{5}=2$

 

(ii) \[\text{36  }\!\!\div\!\!\text{  0}\text{.2 }\]

Ans: Converting the terms in fraction form and calculating the value,

$36\div 0.2=36\div \frac{2}{10}=36\times \frac{10}{2}=18\times 10=180$


(iii) \[\text{3}\text{.25  }\!\!\div\!\!\text{  0}\text{.5}\]  

Ans: Converting the terms in fraction form and calculating the value,$3.25\div 0.5=\frac{325}{100}\div \frac{5}{10}=\frac{325}{100}\times \frac{10}{5}=\frac{65}{10}=6.5$


(iv) \[\text{30}\text{.94  }\!\!\div\!\!\text{  0}\text{.7}\]

Ans: Converting the terms in fraction form and calculating the value,

$30.94\div 0.7=\frac{3094}{100}\div \frac{7}{10}=\frac{3094}{100}\times \frac{10}{7}=\frac{442}{10}=44.2$


(v) \[\text{0}\text{.5  }\!\!\div\!\!\text{  0}\text{.25 }\] 

Ans: Converting the terms in fraction form and calculating the value,$0.5\div 0.25=\frac{5}{10}\div \frac{25}{100}=\frac{5}{10}\times \frac{100}{25}=\frac{10}{5}=2$


(vi) \[\text{7}\text{.75  }\!\!\div\!\!\text{  0}\text{.25}\] 

Ans: Converting the terms in fraction form and calculating the value,

$7.75\div 0.25=\frac{775}{100}\div \frac{25}{100}=\frac{775}{100}\times \frac{100}{25}=31$


(vii) \[\text{76}\text{.5  }\!\!\div\!\!\text{  0}\text{.15}\] 

Ans: Converting the terms in fraction form and calculating the value,

$76.5\div 0.15=\frac{765}{100}\div \frac{15}{100}=\frac{765}{10}\times \frac{100}{15}=51\times 10=510$


(viii) \[\text{37}\text{.8  }\!\!\div\!\!\text{  1}\text{.4}\]

Ans: Converting the terms in fraction form and calculating the value,

$37.8\div 1.4=\frac{378}{10}\div \frac{14}{10}=\frac{378}{10}\times \frac{10}{14}=27$


(ix) \[\text{2}\text{.73  }\!\!\div\!\!\text{  1}\text{.3 }\] 

Ans: Converting the terms in fraction form and calculating the value,

$2.73\div 1.3=\frac{273}{100}\div \frac{13}{10}=\frac{273}{100}\times \frac{10}{13}=\frac{21}{10}=2.1$


6. A vehicle covers a distance of \[\text{43}\text{.2 km}\] in

\[\text{2}\text{.4}\]litres of petrol. How much distance will it cover in one 

litre 

petrol?

Ans: Given:\[\,\,\,\text{In 2}\text{.4 litres of petrol, distance covered by the vehicle = 43}\text{.2 km}\]

Since,\[\,\,\,\text{In 2}\text{.4 litres of petrol, distance covered by the vehicle = 43}\text{.2 km}\]

\[\therefore \,\,\text{In 1 litre of petrol, distance covered by the vehicle = 43}\text{.2  }\!\!\div\!\!\text{  2}\text{.4}\] 

Performing the required calculations,

$=\frac{432}{10}\div \frac{24}{10}=\frac{432}{10}\times \frac{24}{10}$ 

$\text{=18}\,\text{km}$ 

Hence, the vehicle can cover \[\text{18 km}\] distance in one litre of petrol.


NCERT Solutions for Class 7 Chapter 2 Maths PDF Download

2.1 Introduction

In NCERT Solutions Class 7 Chapter 2 Maths, students will learn about fractions and decimals. In junior classes, students have learned about what is a fraction and its types: proper, improper, mixed fractions, etc. Now, in class 7, we are going to learn about multiplication and division of fractions. The concept of fractions mainly focuses on the ratios and proportions, how to distribute etc. At the same time, decimals are the accurate values obtained after the division.

2.2 Recollect

In NCERT Solutions Class 7 Maths Chapter 2, students need to think again on the topics they have learned so far in the previous classes. These include representation of fractions on the number line, ordering of fractions, addition and subtraction of fractions, decimals and their additions, how to keep a point, etc. These are reminded in the first two exercises.

2.3 Multiplication of Fractions

In this section, students can understand how to multiply two fractions. If students have values like a and b, they can say ab is the product of a and b. If the values are like p/q, a/b then, how can we multiply? To multiply these fractions, it has two different methods. One is by using a  whole number and the other is by using a portion.

2.3.1 Multiplication of Fractions Using the Whole Number

Here, let us see what Fraction tells us? It explains that a down part is a whole number (except zero) and the upper part is the integer. In a fraction, the down part is known as the denominator whereas the upper part is the numerator. We use a whole number to multiply fractions if they are the same. For instance, let's say we have p/q. Then we can multiply with the whole number as 3*p/q. It is also applicable for improper or mixed fractions. But students need to make them into simpler forms before multiplying.

2.3.1 Multiplication of Fractions Using the Fraction

In this section, students can learn how to multiply two fractions when they are dissimilar. Students use a fraction to multiply them. The formula for multiplying two fractions is,(product of numerators)/(product of denominators).

 

The resultant product is less than the two fractions if we multiply two proper fractions. On the other hand, the result is greater than the two fractions if we multiply two improper fractions.

2.4 Division of Fractions

Let's discuss the division of fractions. Students can divide a fraction by a whole number and a whole number by a fraction. Here is a particular case to keep in mind. If two fractions for which numerator and denominator are in reverse order, then they are called reciprocals to each other.  Their product is always 1.


In the same way, while dividing mixed fractions with a whole number, students need to change the mixed fraction into improper fractions. Then it is easy to divide and solve. Next, we have to learn to divide a fraction with another fraction by changing one of the fractions into its reciprocal form.


The three concepts are explained differently in the NCERT Solutions for Class 7 Maths Chapter 2 PDF book available on Vedantu for students to go through if necessary.

2.5 Recalling Decimals

Decimals are the proper forms to represent the results obtained from multiplication and division. Placing the point in between numbers plays a vital role. One can express the heights, distances, weights,  measuring values, interest rates, shares, and fractions, also using decimals. To change the place value of the point, we can multiply by 10,100,...... Let's have a glance at the addition and subtraction of decimals.


Overview of Deleted Syllabus for CBSE Class 7 Maths Chapter 2 Fractions and Decimals

Chapter

Dropped Topics

Fractions and Decimals

2.1 - Introduction

2.2 - How well have you learned about fractions

2.5 - How well have you learned about decimals.



Class 7 Maths Chapter 2: Exercises Breakdown

Chapter 2 - Fraction and Decimals Class 7 Exercises in PDF Format

Exercise 2.1

8 Questions & Solutions

Exercise 2.2

8 Questions & Solutions

Exercise 2.3

4 Questions & Solutions

Exercise 2.4

5 Questions & Solutions

Exercise 2.5

6 Questions & Solutions



Conclusion

NCERT Solutions for Chapter 2 fraction and decimals Class 7 offers practice problems and clear explanations to help master these concepts. Students should focus on fraction addition, subtraction, multiplication, and division for both like and unlike denominators. They should also be able to convert between fractions and decimals easily and understand relative fraction sizes. By carefully working through NCERT Class 7 Maths Chapter 2 Exercises, students can improve their knowledge and prepare for exams.


Other Study Material for CBSE Class 7 Maths Chapter 2



Chapter-Specific NCERT Solutions for Class 7 Maths

Given below are the chapter-wise NCERT Solutions for Class 7 Maths. Go through these chapter-wise solutions to be thoroughly familiar with the concepts.


FAQs on NCERT Solutions Class 7 Maths Chapter 2 Fractions and Decimals

1. What are the main topics and subtopics covered in chapter 2 of Class 7 Maths?

Topics and sub-topics discussed in Chapter 2 Fractions and Decimals of NCERT Solutions Class 7 Maths are: Addition and Subtraction of Fractions, Multiplication of Fraction, Multiplication of a Fraction by a Whole Number, Multiplication of a Fraction by a Fraction, Division of Fraction, Division of Whole Number by a Fraction, Reciprocal of Fraction, Division of a fraction by a Whole Number, Division of Fraction by Another Fraction, Multiplication of Decimal Numbers, Multiplication of Decimal Numbers by 10, 100 and 1000, Division of Decimal Numbers, Division of Decimals by 10, 100 and 1000, Division of a Decimal Number by a Whole Number and Division of a Decimal Number by Another Decimal Number.

2. How many questions are there in exercises of chapter 2 of Class 7 Maths?

There are a total of seven exercises given in the second chapter of Class 7 Maths. Exercise 2.1 has 8 questions, exercise 2.2 has 8 questions, exercise 2.3 has 8 questions, exercise 2.4 has 4 questions, exercise 2.5 has 9 questions, exercise 2.6 has 5 questions, and exercise 2.7 has 6 questions.

3. How do I compare two fractions class 7 maths ch 2?

By examining the numerators, fractions with the same denominator can be compared. It is a larger fraction with a larger numerator. You can convert fractions with different denominators to equivalent fractions with the same denominator so that you can compare them.

4. What are the different types of fractions?

There are three main types of fractions: proper fractions, improper fractions, and mixed numbers.

  • Proper fractions: These are fractions whose numerator is smaller than the denominator. For example, 1/2 and 3/5 are proper fractions.

  • Improper fractions: These are fractions whose numerator is larger than or equal to the denominator. For example, 5/3 and 8/2 are improper fractions.

  • Mixed numbers: These are numbers that are made up of a whole number and a fraction. For example, 2 1/2 is a mixed number.

5. What are the different types of decimals?

There are two main types of decimals: terminating decimals and non-terminating decimals.

  • Terminating decimals: These are decimals that end after a finite number of digits. For example, 0.5 and 1.23 are terminating decimals.

  • Non-terminating decimals: These are decimals that do not end after a finite number of digits. For example, 1/3 and 1/2 are non-terminating decimals.

6. What are the uses of fractions and decimals?

Fractions and decimals are used in a variety of ways in mathematics and everyday life.

  • In mathematics, fractions and decimals are used to represent parts of a whole, to perform arithmetic operations, and to solve equations.

  • In everyday life, fractions and decimals are used to represent quantities such as money, time, and measurements.

7. What's important in class 7th maths chapter 2 ?

This chapter covers various aspects of fractions and decimals in class 7th maths chapter 2 . Here's what to focus on:

  • Understanding different types of fractions (proper, improper, mixed)

  • Converting between fractions and decimals

  • Comparing and ordering fractions

  • Adding and subtracting fractions and decimals

  • Representing fractions on the number line

8. What are like terms in addition and subtraction of fractions in class 7 chapter 2 maths?

Like terms in fractions, they have the same denominator. When adding or subtracting fractions, make sure they have the same denominator before performing the operation.

9. How do I represent fractions on the number line in fraction and decimals class7?

Divide the space between two whole numbers on the number line according to the denominator of the fraction. Each small interval represents 1/denominator. Shade the required number of intervals based on the numerator.